How much of a pesticide containing 10% active ingredient should be added to water to prepare 3 gallons of spray mixture if 3 oz. of active ingredient is recommended per gallon?

Prepare for the Tennessee Ornamental and Turf Pest Control Exam. Test your knowledge with multiple-choice questions, each accompanied by hints and explanations. Get ready for your certification!

To determine how much of a pesticide containing 10% active ingredient is required to prepare 3 gallons of spray mixture with a recommendation of 3 ounces of active ingredient per gallon, we first need to calculate the total amount of active ingredient needed for the entire 3 gallons.

Since the recommendation is 3 ounces of active ingredient per gallon, for 3 gallons, the calculation is as follows:

3 ounces/gallon × 3 gallons = 9 ounces of active ingredient.

Next, we need to find out how much of the pesticide solution is required to obtain 9 ounces of active ingredient. Given that the pesticide contains 10% active ingredient, this means that in every 100 ounces of pesticide solution, there are 10 ounces of active ingredient. Therefore, to find out how many ounces of pesticide solution are needed to get 9 ounces of active ingredient, we can use the following proportion:

If 10 ounces are in 100 ounces of pesticide, then 9 ounces of active ingredient would be in:

(9 ounces of active ingredient) / (10 ounces of active ingredient per 100 ounces of pesticide) = 90 ounces of pesticide.

Thus, to prepare 3 gallons of spray mixture that contains the recommended amount of active ingredient,

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy